Base | Representation |
---|---|
bin | 100100110110010001011… |
… | …1101110101011110010011 |
3 | 122221010222110210011101122 |
4 | 1021230202331311132103 |
5 | 1130433243341432024 |
6 | 14434310502152455 |
7 | 1031613250614626 |
oct | 111544275653623 |
9 | 18833873704348 |
10 | 5064353077139 |
11 | 1682864314934 |
12 | 69960972272b |
13 | 2a9749635835 |
14 | 13718a41bdbd |
15 | 8bb071ded5e |
hex | 49b22f75793 |
5064353077139 has 2 divisors, whose sum is σ = 5064353077140. Its totient is φ = 5064353077138.
The previous prime is 5064353077117. The next prime is 5064353077193. The reversal of 5064353077139 is 9317703534605.
Together with next prime (5064353077193) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5064353077139 - 236 = 4995633600403 is a prime.
It is not a weakly prime, because it can be changed into another prime (5064353077639) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2532176538569 + 2532176538570.
It is an arithmetic number, because the mean of its divisors is an integer number (2532176538570).
Almost surely, 25064353077139 is an apocalyptic number.
5064353077139 is a deficient number, since it is larger than the sum of its proper divisors (1).
5064353077139 is an equidigital number, since it uses as much as digits as its factorization.
5064353077139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7144200, while the sum is 53.
The spelling of 5064353077139 in words is "five trillion, sixty-four billion, three hundred fifty-three million, seventy-seven thousand, one hundred thirty-nine".
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