Base | Representation |
---|---|
bin | 100100110111010101111… |
… | …0101110011010110110101 |
3 | 122221100220111210222121222 |
4 | 1021232223311303112311 |
5 | 1131002444224344114 |
6 | 14435330413320125 |
7 | 1032024203511155 |
oct | 111565365632665 |
9 | 18840814728558 |
10 | 5066649449909 |
11 | 1683832588773 |
12 | 699b4a796045 |
13 | 2a9a2430a9a8 |
14 | 1373273c4765 |
15 | 8bbddae698e |
hex | 49babd735b5 |
5066649449909 has 2 divisors, whose sum is σ = 5066649449910. Its totient is φ = 5066649449908.
The previous prime is 5066649449821. The next prime is 5066649449923. The reversal of 5066649449909 is 9099449466605.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4745086735684 + 321562714225 = 2178322^2 + 567065^2 .
It is a cyclic number.
It is not a de Polignac number, because 5066649449909 - 232 = 5062354482613 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5066649449959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2533324724954 + 2533324724955.
It is an arithmetic number, because the mean of its divisors is an integer number (2533324724955).
Almost surely, 25066649449909 is an apocalyptic number.
It is an amenable number.
5066649449909 is a deficient number, since it is larger than the sum of its proper divisors (1).
5066649449909 is an equidigital number, since it uses as much as digits as its factorization.
5066649449909 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 453496320, while the sum is 71.
The spelling of 5066649449909 in words is "five trillion, sixty-six billion, six hundred forty-nine million, four hundred forty-nine thousand, nine hundred nine".
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