Base | Representation |
---|---|
bin | 10111000011000001100100… |
… | …10000100000100010001111 |
3 | 20122110002200220020221120121 |
4 | 23201200302100200202033 |
5 | 23120331111030444132 |
6 | 255442423503525411 |
7 | 13450420520634646 |
oct | 1341406220404217 |
9 | 218402626227517 |
10 | 50681457281167 |
11 | 1516a981410669 |
12 | 58264a55b9867 |
13 | 223831939b32b |
14 | c72dd1daa35d |
15 | 5cd51ada8497 |
hex | 2e183242088f |
50681457281167 has 2 divisors, whose sum is σ = 50681457281168. Its totient is φ = 50681457281166.
The previous prime is 50681457281129. The next prime is 50681457281263. The reversal of 50681457281167 is 76118275418605.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50681457281167 - 211 = 50681457279119 is a prime.
It is a super-2 number, since 2×506814572811672 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50681457281267) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25340728640583 + 25340728640584.
It is an arithmetic number, because the mean of its divisors is an integer number (25340728640584).
Almost surely, 250681457281167 is an apocalyptic number.
50681457281167 is a deficient number, since it is larger than the sum of its proper divisors (1).
50681457281167 is an equidigital number, since it uses as much as digits as its factorization.
50681457281167 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 22579200, while the sum is 61.
The spelling of 50681457281167 in words is "fifty trillion, six hundred eighty-one billion, four hundred fifty-seven million, two hundred eighty-one thousand, one hundred sixty-seven".
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