Base | Representation |
---|---|
bin | 100100111001001000110… |
… | …1111101110001000101101 |
3 | 122221201212022202021212221 |
4 | 1021302101233232020231 |
5 | 1131033344143142331 |
6 | 14441205241555341 |
7 | 1032221611050346 |
oct | 111622157561055 |
9 | 18851768667787 |
10 | 5070506615341 |
11 | 16854318841a2 |
12 | 69a8464a5b51 |
13 | 2aa1ba46babb |
14 | 1375b17970cd |
15 | 8bd67555711 |
hex | 49c91bee22d |
5070506615341 has 2 divisors, whose sum is σ = 5070506615342. Its totient is φ = 5070506615340.
The previous prime is 5070506615299. The next prime is 5070506615353. The reversal of 5070506615341 is 1435166050705.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5065105835241 + 5400780100 = 2250579^2 + 73490^2 .
It is a cyclic number.
It is not a de Polignac number, because 5070506615341 - 29 = 5070506614829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5070506616341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2535253307670 + 2535253307671.
It is an arithmetic number, because the mean of its divisors is an integer number (2535253307671).
Almost surely, 25070506615341 is an apocalyptic number.
It is an amenable number.
5070506615341 is a deficient number, since it is larger than the sum of its proper divisors (1).
5070506615341 is an equidigital number, since it uses as much as digits as its factorization.
5070506615341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 378000, while the sum is 43.
The spelling of 5070506615341 in words is "five trillion, seventy billion, five hundred six million, six hundred fifteen thousand, three hundred forty-one".
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