Base | Representation |
---|---|
bin | 101111010001100111… |
… | …011101010011001111 |
3 | 11212000122120102021211 |
4 | 233101213131103033 |
5 | 1312424411001111 |
6 | 35153001235251 |
7 | 3444625653025 |
oct | 572147352317 |
9 | 155018512254 |
10 | 50761422031 |
11 | 1a589554761 |
12 | 9a07a92b27 |
13 | 4a2c7363c8 |
14 | 26578d6715 |
15 | 14c164b521 |
hex | bd19dd4cf |
50761422031 has 2 divisors, whose sum is σ = 50761422032. Its totient is φ = 50761422030.
The previous prime is 50761421959. The next prime is 50761422043. The reversal of 50761422031 is 13022416705.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50761422031 - 27 = 50761421903 is a prime.
It is a super-2 number, since 2×507614220312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 50761421984 and 50761422002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50761422071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25380711015 + 25380711016.
It is an arithmetic number, because the mean of its divisors is an integer number (25380711016).
Almost surely, 250761422031 is an apocalyptic number.
50761422031 is a deficient number, since it is larger than the sum of its proper divisors (1).
50761422031 is an equidigital number, since it uses as much as digits as its factorization.
50761422031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 31.
Adding to 50761422031 its reverse (13022416705), we get a palindrome (63783838736).
The spelling of 50761422031 in words is "fifty billion, seven hundred sixty-one million, four hundred twenty-two thousand, thirty-one".
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