Base | Representation |
---|---|
bin | 10111000101100101010111… |
… | …01100111100110001011001 |
3 | 20122202111200100221111202101 |
4 | 23202302223230330301121 |
5 | 23123301204344012123 |
6 | 255551045423403401 |
7 | 13456652625531421 |
oct | 1342625354746131 |
9 | 218674610844671 |
10 | 50769394125913 |
11 | 151a41a7479671 |
12 | 583b547453561 |
13 | 22436c1933088 |
14 | c77374c8d481 |
15 | 5d0966049aad |
hex | 2e2cabb3cc59 |
50769394125913 has 2 divisors, whose sum is σ = 50769394125914. Its totient is φ = 50769394125912.
The previous prime is 50769394125881. The next prime is 50769394125937. The reversal of 50769394125913 is 31952149396705.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 50729108818969 + 40285306944 = 7122437^2 + 200712^2 .
It is a cyclic number.
It is not a de Polignac number, because 50769394125913 - 25 = 50769394125881 is a prime.
It is not a weakly prime, because it can be changed into another prime (50769394125113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25384697062956 + 25384697062957.
It is an arithmetic number, because the mean of its divisors is an integer number (25384697062957).
Almost surely, 250769394125913 is an apocalyptic number.
It is an amenable number.
50769394125913 is a deficient number, since it is larger than the sum of its proper divisors (1).
50769394125913 is an equidigital number, since it uses as much as digits as its factorization.
50769394125913 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55112400, while the sum is 64.
The spelling of 50769394125913 in words is "fifty trillion, seven hundred sixty-nine billion, three hundred ninety-four million, one hundred twenty-five thousand, nine hundred thirteen".
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