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507699341 is a prime number
BaseRepresentation
bin11110010000101…
…110000010001101
31022101022210120022
4132100232002031
52014432334331
6122213431525
715403242002
oct3620560215
91271283508
10507699341
11240646036
1212203b5a5
138124c716
144b5db8a9
152e88967b
hex1e42e08d

507699341 has 2 divisors, whose sum is σ = 507699342. Its totient is φ = 507699340.

The previous prime is 507699331. The next prime is 507699371. The reversal of 507699341 is 143996705.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 278055625 + 229643716 = 16675^2 + 15154^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-507699341 is a prime.

It is a Chen prime.

It is equal to p26739476 and since 507699341 and 26739476 have the same sum of digits, it is a Honaker prime.

It is a junction number, because it is equal to n+sod(n) for n = 507699292 and 507699301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (507699301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 253849670 + 253849671.

It is an arithmetic number, because the mean of its divisors is an integer number (253849671).

Almost surely, 2507699341 is an apocalyptic number.

It is an amenable number.

507699341 is a deficient number, since it is larger than the sum of its proper divisors (1).

507699341 is an equidigital number, since it uses as much as digits as its factorization.

507699341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 204120, while the sum is 44.

The square root of 507699341 is about 22532.1845589814. The cubic root of 507699341 is about 797.7537724174.

The spelling of 507699341 in words is "five hundred seven million, six hundred ninety-nine thousand, three hundred forty-one".