Base | Representation |
---|---|
bin | 100100111101010010111… |
… | …1100010111000100100101 |
3 | 122222120220120211221022111 |
4 | 1021322211330113010211 |
5 | 1131210140431021103 |
6 | 14445243241001021 |
7 | 1032656100404665 |
oct | 111724574270445 |
9 | 18876816757274 |
10 | 5079435407653 |
11 | 16891a3959aa2 |
12 | 6a0518783171 |
13 | 2aacb1249969 |
14 | 137bbb5541a5 |
15 | 8c1db36886d |
hex | 49ea5f17125 |
5079435407653 has 2 divisors, whose sum is σ = 5079435407654. Its totient is φ = 5079435407652.
The previous prime is 5079435407623. The next prime is 5079435407663. The reversal of 5079435407653 is 3567045349705.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4704183601569 + 375251806084 = 2168913^2 + 612578^2 .
It is a cyclic number.
It is not a de Polignac number, because 5079435407653 - 237 = 4941996454181 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5079435407623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2539717703826 + 2539717703827.
It is an arithmetic number, because the mean of its divisors is an integer number (2539717703827).
Almost surely, 25079435407653 is an apocalyptic number.
It is an amenable number.
5079435407653 is a deficient number, since it is larger than the sum of its proper divisors (1).
5079435407653 is an equidigital number, since it uses as much as digits as its factorization.
5079435407653 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 47628000, while the sum is 58.
The spelling of 5079435407653 in words is "five trillion, seventy-nine billion, four hundred thirty-five million, four hundred seven thousand, six hundred fifty-three".
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