Base | Representation |
---|---|
bin | 101111010011101011… |
… | …010111001101100111 |
3 | 11212010001122011111011 |
4 | 233103223113031213 |
5 | 1313012234000403 |
6 | 35200234323051 |
7 | 3445525606522 |
oct | 572353271547 |
9 | 155101564434 |
10 | 50796000103 |
11 | 1a5a7021782 |
12 | 9a17589487 |
13 | 4a369520c4 |
14 | 265c337bb9 |
15 | 14c46cba6d |
hex | bd3ad7367 |
50796000103 has 2 divisors, whose sum is σ = 50796000104. Its totient is φ = 50796000102.
The previous prime is 50796000067. The next prime is 50796000109. The reversal of 50796000103 is 30100069705.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50796000103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50796000109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25398000051 + 25398000052.
It is an arithmetic number, because the mean of its divisors is an integer number (25398000052).
Almost surely, 250796000103 is an apocalyptic number.
50796000103 is a deficient number, since it is larger than the sum of its proper divisors (1).
50796000103 is an equidigital number, since it uses as much as digits as its factorization.
50796000103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5670, while the sum is 31.
Adding to 50796000103 its reverse (30100069705), we get a palindrome (80896069808).
The spelling of 50796000103 in words is "fifty billion, seven hundred ninety-six million, one hundred three", and thus it is an aban number.
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