Base | Representation |
---|---|
bin | 100100111111000101011… |
… | …0111111100111011100111 |
3 | 122222221211021001011012121 |
4 | 1021332022313330323213 |
5 | 1131241022204000341 |
6 | 14451120323130411 |
7 | 1033153216034551 |
oct | 111761267747347 |
9 | 18887737034177 |
10 | 5083276234471 |
11 | 168a894a06036 |
12 | 6a120ab13a07 |
13 | 2ab473baa056 |
14 | 1380636b24d1 |
15 | 8c36364b4d1 |
hex | 49f8adfcee7 |
5083276234471 has 2 divisors, whose sum is σ = 5083276234472. Its totient is φ = 5083276234470.
The previous prime is 5083276234447. The next prime is 5083276234481. The reversal of 5083276234471 is 1744326723805.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5083276234471 - 225 = 5083242680039 is a prime.
It is a super-3 number, since 3×50832762344713 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5083276234481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2541638117235 + 2541638117236.
It is an arithmetic number, because the mean of its divisors is an integer number (2541638117236).
Almost surely, 25083276234471 is an apocalyptic number.
5083276234471 is a deficient number, since it is larger than the sum of its proper divisors (1).
5083276234471 is an equidigital number, since it uses as much as digits as its factorization.
5083276234471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6773760, while the sum is 52.
The spelling of 5083276234471 in words is "five trillion, eighty-three billion, two hundred seventy-six million, two hundred thirty-four thousand, four hundred seventy-one".
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