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50848992253 is a prime number
BaseRepresentation
bin101111010110110101…
…100000101111111101
311212020202100110001101
4233112311200233331
51313114320223003
635205410213101
73450041205553
oct572665405775
9155222313041
1050848992253
111a623a26544
129a31284191
134a449173c7
1426653adbd3
1514c919811d
hexbd6d60bfd

50848992253 has 2 divisors, whose sum is σ = 50848992254. Its totient is φ = 50848992252.

The previous prime is 50848992239. The next prime is 50848992277. The reversal of 50848992253 is 35229984805.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 47547110809 + 3301881444 = 218053^2 + 57462^2 .

It is a cyclic number.

It is not a de Polignac number, because 50848992253 - 29 = 50848991741 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 50848992194 and 50848992203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50848992853) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25424496126 + 25424496127.

It is an arithmetic number, because the mean of its divisors is an integer number (25424496127).

Almost surely, 250848992253 is an apocalyptic number.

It is an amenable number.

50848992253 is a deficient number, since it is larger than the sum of its proper divisors (1).

50848992253 is an equidigital number, since it uses as much as digits as its factorization.

50848992253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6220800, while the sum is 55.

The spelling of 50848992253 in words is "fifty billion, eight hundred forty-eight million, nine hundred ninety-two thousand, two hundred fifty-three".