Base | Representation |
---|---|
bin | 100101000001010011000… |
… | …1101110100000101101011 |
3 | 200000102002112221021110202 |
4 | 1022002212031310011223 |
5 | 1131330241124330142 |
6 | 14453224135102415 |
7 | 1033412060500103 |
oct | 112024615640553 |
9 | 20012075837422 |
10 | 5088029917547 |
11 | 1691904275535 |
12 | 6a2116b11a0b |
13 | 2aba509b5785 |
14 | 138394b76203 |
15 | 8c540b4a032 |
hex | 4a0a637416b |
5088029917547 has 2 divisors, whose sum is σ = 5088029917548. Its totient is φ = 5088029917546.
The previous prime is 5088029917513. The next prime is 5088029917549. The reversal of 5088029917547 is 7457199208805.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5088029917547 - 218 = 5088029655403 is a prime.
Together with 5088029917549, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (5088029917549) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2544014958773 + 2544014958774.
It is an arithmetic number, because the mean of its divisors is an integer number (2544014958774).
Almost surely, 25088029917547 is an apocalyptic number.
5088029917547 is a deficient number, since it is larger than the sum of its proper divisors (1).
5088029917547 is an equidigital number, since it uses as much as digits as its factorization.
5088029917547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 50803200, while the sum is 65.
The spelling of 5088029917547 in words is "five trillion, eighty-eight billion, twenty-nine million, nine hundred seventeen thousand, five hundred forty-seven".
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