Base | Representation |
---|---|
bin | 101111011111111001… |
… | …110101010110111101 |
3 | 11212122100121100100101 |
4 | 233133321311112331 |
5 | 1313422241321224 |
6 | 35232443001101 |
7 | 3453566240335 |
oct | 573771652675 |
9 | 155570540311 |
10 | 51001120189 |
11 | 1a6a1891508 |
12 | 9a74209191 |
13 | 4a6a2aca36 |
14 | 267b6900c5 |
15 | 14d76e8044 |
hex | bdfe755bd |
51001120189 has 2 divisors, whose sum is σ = 51001120190. Its totient is φ = 51001120188.
The previous prime is 51001120171. The next prime is 51001120223. The reversal of 51001120189 is 98102110015.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50239636164 + 761484025 = 224142^2 + 27595^2 .
It is a cyclic number.
It is not a de Polignac number, because 51001120189 - 221 = 50999023037 is a prime.
It is a super-4 number, since 4×510011201894 (a number of 44 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51001120129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25500560094 + 25500560095.
It is an arithmetic number, because the mean of its divisors is an integer number (25500560095).
Almost surely, 251001120189 is an apocalyptic number.
It is an amenable number.
51001120189 is a deficient number, since it is larger than the sum of its proper divisors (1).
51001120189 is an equidigital number, since it uses as much as digits as its factorization.
51001120189 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 28.
The spelling of 51001120189 in words is "fifty-one billion, one million, one hundred twenty thousand, one hundred eighty-nine".
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