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5100343153 is a prime number
BaseRepresentation
bin1001100000000000…
…10000111101110001
3111011110012021111021
410300000100331301
540421141440103
62202034015441
7240251126053
oct46000207561
914143167437
105100343153
112188013334
12ba4117581
13633892639
143655418d3
151ecb77bbd
hex130010f71

5100343153 has 2 divisors, whose sum is σ = 5100343154. Its totient is φ = 5100343152.

The previous prime is 5100343093. The next prime is 5100343177. The reversal of 5100343153 is 3513430015.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5068443249 + 31899904 = 71193^2 + 5648^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5100343153 is a prime.

It is a super-3 number, since 3×51003431533 (a number of 30 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (5100343453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2550171576 + 2550171577.

It is an arithmetic number, because the mean of its divisors is an integer number (2550171577).

Almost surely, 25100343153 is an apocalyptic number.

It is an amenable number.

5100343153 is a deficient number, since it is larger than the sum of its proper divisors (1).

5100343153 is an equidigital number, since it uses as much as digits as its factorization.

5100343153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2700, while the sum is 25.

The square root of 5100343153 is about 71416.6867965744. The cubic root of 5100343153 is about 1721.3392257083.

Adding to 5100343153 its reverse (3513430015), we get a palindrome (8613773168).

The spelling of 5100343153 in words is "five billion, one hundred million, three hundred forty-three thousand, one hundred fifty-three".