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51011500513 is a prime number
BaseRepresentation
bin101111100000100001…
…011011100111100001
311212200002010201110211
4233200201123213201
51313432421004023
635233453254121
73454053412561
oct574041334741
9155602121424
1051011500513
111a6a7731396
129a77794341
134a6c4a573c
14267cbd2da1
1514d8598a0d
hexbe085b9e1

51011500513 has 2 divisors, whose sum is σ = 51011500514. Its totient is φ = 51011500512.

The previous prime is 51011500489. The next prime is 51011500537. The reversal of 51011500513 is 31500511015.

51011500513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (51011500489) and next prime (51011500537).

It can be written as a sum of positive squares in only one way, i.e., 37301900769 + 13709599744 = 193137^2 + 117088^2 .

It is a cyclic number.

It is not a de Polignac number, because 51011500513 - 25 = 51011500481 is a prime.

It is not a weakly prime, because it can be changed into another prime (51011503513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25505750256 + 25505750257.

It is an arithmetic number, because the mean of its divisors is an integer number (25505750257).

Almost surely, 251011500513 is an apocalyptic number.

It is an amenable number.

51011500513 is a deficient number, since it is larger than the sum of its proper divisors (1).

51011500513 is an equidigital number, since it uses as much as digits as its factorization.

51011500513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 375, while the sum is 22.

The spelling of 51011500513 in words is "fifty-one billion, eleven million, five hundred thousand, five hundred thirteen".