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5101313341 is a prime number
BaseRepresentation
bin1001100000000111…
…11101110100111101
3111011112000120100011
410300003331310331
540421414011331
62202110503221
7240262306435
oct46003756475
914145016304
105101313341
112188616243
12ba4504b11
13633b42107
143657152c5
151eccba3b1
hex1300fdd3d

5101313341 has 2 divisors, whose sum is σ = 5101313342. Its totient is φ = 5101313340.

The previous prime is 5101313333. The next prime is 5101313351. The reversal of 5101313341 is 1433131015.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3006328900 + 2094984441 = 54830^2 + 45771^2 .

It is a cyclic number.

It is not a de Polignac number, because 5101313341 - 23 = 5101313333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5101313311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2550656670 + 2550656671.

It is an arithmetic number, because the mean of its divisors is an integer number (2550656671).

Almost surely, 25101313341 is an apocalyptic number.

It is an amenable number.

5101313341 is a deficient number, since it is larger than the sum of its proper divisors (1).

5101313341 is an equidigital number, since it uses as much as digits as its factorization.

5101313341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 22.

The square root of 5101313341 is about 71423.4789197502. The cubic root of 5101313341 is about 1721.4483632527.

Adding to 5101313341 its reverse (1433131015), we get a palindrome (6534444356).

The spelling of 5101313341 in words is "five billion, one hundred one million, three hundred thirteen thousand, three hundred forty-one".