Base | Representation |
---|---|
bin | 1110110110001100011… |
… | …00111001110010101111 |
3 | 1210202201221020202221022 |
4 | 13123012030321302233 |
5 | 31324222120142033 |
6 | 1030203502324355 |
7 | 51566350313153 |
oct | 7330614716257 |
9 | 1722657222838 |
10 | 510131412143 |
11 | 187388979391 |
12 | 82a49b896bb |
13 | 3914a1296c2 |
14 | 1a9949d3063 |
15 | d40a2ed098 |
hex | 76c6339caf |
510131412143 has 2 divisors, whose sum is σ = 510131412144. Its totient is φ = 510131412142.
The previous prime is 510131412107. The next prime is 510131412163. The reversal of 510131412143 is 341214131015.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 510131412143 - 214 = 510131395759 is a prime.
It is a super-2 number, since 2×5101314121432 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (510131412163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255065706071 + 255065706072.
It is an arithmetic number, because the mean of its divisors is an integer number (255065706072).
Almost surely, 2510131412143 is an apocalyptic number.
510131412143 is a deficient number, since it is larger than the sum of its proper divisors (1).
510131412143 is an equidigital number, since it uses as much as digits as its factorization.
510131412143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 510131412143 its reverse (341214131015), we get a palindrome (851345543158).
The spelling of 510131412143 in words is "five hundred ten billion, one hundred thirty-one million, four hundred twelve thousand, one hundred forty-three".
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