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51013254141431 is a prime number
BaseRepresentation
bin10111001100101011100101…
…11001000101010111110111
320200121211010101120211120222
423212111302321011113313
523141300121030011211
6300255055422044555
713513404664465661
oct1346256271052767
9220554111524528
1051013254141431
111528866606067a
12587a86371975b
1322606b5922c4a
14c850aa053531
155d6e89cc91db
hex2e6572e455f7

51013254141431 has 2 divisors, whose sum is σ = 51013254141432. Its totient is φ = 51013254141430.

The previous prime is 51013254141427. The next prime is 51013254141457. The reversal of 51013254141431 is 13414145231015.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 51013254141431 - 22 = 51013254141427 is a prime.

It is a super-2 number, since 2×510132541414312 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51013254141391 and 51013254141400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51013254141481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25506627070715 + 25506627070716.

It is an arithmetic number, because the mean of its divisors is an integer number (25506627070716).

Almost surely, 251013254141431 is an apocalyptic number.

51013254141431 is a deficient number, since it is larger than the sum of its proper divisors (1).

51013254141431 is an equidigital number, since it uses as much as digits as its factorization.

51013254141431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 35.

Adding to 51013254141431 its reverse (13414145231015), we get a palindrome (64427399372446).

The spelling of 51013254141431 in words is "fifty-one trillion, thirteen billion, two hundred fifty-four million, one hundred forty-one thousand, four hundred thirty-one".