Base | Representation |
---|---|
bin | 1001100000001000… |
… | …00010010001111101 |
3 | 111011112001111100201 |
4 | 10300010002101331 |
5 | 40421420102311 |
6 | 2202111123501 |
7 | 240262413553 |
oct | 46004022175 |
9 | 14145044321 |
10 | 5101331581 |
11 | 2188628a15 |
12 | ba4513591 |
13 | 633b4a4c8 |
14 | 36571bbd3 |
15 | 1eccc09c1 |
hex | 13010247d |
5101331581 has 2 divisors, whose sum is σ = 5101331582. Its totient is φ = 5101331580.
The previous prime is 5101331569. The next prime is 5101331629. The reversal of 5101331581 is 1851331015.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4979560356 + 121771225 = 70566^2 + 11035^2 .
It is a cyclic number.
It is not a de Polignac number, because 5101331581 - 27 = 5101331453 is a prime.
It is a super-2 number, since 2×51013315812 = 52047167798615919122, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5101331381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2550665790 + 2550665791.
It is an arithmetic number, because the mean of its divisors is an integer number (2550665791).
Almost surely, 25101331581 is an apocalyptic number.
It is an amenable number.
5101331581 is a deficient number, since it is larger than the sum of its proper divisors (1).
5101331581 is an equidigital number, since it uses as much as digits as its factorization.
5101331581 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 28.
The square root of 5101331581 is about 71423.6066087397. The cubic root of 5101331581 is about 1721.4504149584.
Adding to 5101331581 its reverse (1851331015), we get a palindrome (6952662596).
The spelling of 5101331581 in words is "five billion, one hundred one million, three hundred thirty-one thousand, five hundred eighty-one".
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