Base | Representation |
---|---|
bin | 100101000111100100111… |
… | …1001101001011000000011 |
3 | 200001200220020200212102121 |
4 | 1022033021321221120003 |
5 | 1132040344424344301 |
6 | 14503334123225111 |
7 | 1034400155244316 |
oct | 112171171513003 |
9 | 20050806625377 |
10 | 5101513512451 |
11 | 16975a34219a4 |
12 | 6a485a678197 |
13 | 2b00bc3174b5 |
14 | 138cb382697d |
15 | 8ca7e7743a1 |
hex | 4a3c9e69603 |
5101513512451 has 2 divisors, whose sum is σ = 5101513512452. Its totient is φ = 5101513512450.
The previous prime is 5101513512437. The next prime is 5101513512467. The reversal of 5101513512451 is 1542153151015.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5101513512451 - 223 = 5101505123843 is a prime.
It is not a weakly prime, because it can be changed into another prime (5101513512551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2550756756225 + 2550756756226.
It is an arithmetic number, because the mean of its divisors is an integer number (2550756756226).
Almost surely, 25101513512451 is an apocalyptic number.
5101513512451 is a deficient number, since it is larger than the sum of its proper divisors (1).
5101513512451 is an equidigital number, since it uses as much as digits as its factorization.
5101513512451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15000, while the sum is 34.
Adding to 5101513512451 its reverse (1542153151015), we get a palindrome (6643666663466).
The spelling of 5101513512451 in words is "five trillion, one hundred one billion, five hundred thirteen million, five hundred twelve thousand, four hundred fifty-one".
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