Base | Representation |
---|---|
bin | 1001100000001010… |
… | …11100010000010001 |
3 | 111011112202012220001 |
4 | 10300011130100101 |
5 | 40422013400423 |
6 | 2202123050001 |
7 | 240265510156 |
oct | 46005342021 |
9 | 14145665801 |
10 | 5101700113 |
11 | 218885a894 |
12 | ba4670901 |
13 | 633c49183 |
14 | 3657b622d |
15 | 1ecd44cad |
hex | 13015c411 |
5101700113 has 2 divisors, whose sum is σ = 5101700114. Its totient is φ = 5101700112.
The previous prime is 5101700111. The next prime is 5101700141. The reversal of 5101700113 is 3110071015.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3955403664 + 1146296449 = 62892^2 + 33857^2 .
It is a cyclic number.
It is not a de Polignac number, because 5101700113 - 21 = 5101700111 is a prime.
Together with 5101700111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (5101700111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2550850056 + 2550850057.
It is an arithmetic number, because the mean of its divisors is an integer number (2550850057).
Almost surely, 25101700113 is an apocalyptic number.
It is an amenable number.
5101700113 is a deficient number, since it is larger than the sum of its proper divisors (1).
5101700113 is an equidigital number, since it uses as much as digits as its factorization.
5101700113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 105, while the sum is 19.
The square root of 5101700113 is about 71426.1864654694. The cubic root of 5101700113 is about 1721.4918678142.
Adding to 5101700113 its reverse (3110071015), we get a palindrome (8211771128).
The spelling of 5101700113 in words is "five billion, one hundred one million, seven hundred thousand, one hundred thirteen".
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