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51018131 is a prime number
BaseRepresentation
bin1100001010011…
…1100110010011
310112222222201102
43002213212103
5101030040011
65021255015
71156434623
oct302474623
9115888642
1051018131
112688674a
121510446b
13a753958
146ac0883
15472b73b
hex30a7993

51018131 has 2 divisors, whose sum is σ = 51018132. Its totient is φ = 51018130.

The previous prime is 51018113. The next prime is 51018133. The reversal of 51018131 is 13181015.

51018131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (51018113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 51018131 - 210 = 51017107 is a prime.

It is a super-2 number, since 2×510181312 = 5205699381466322, which contains 22 as substring.

Together with 51018133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (51018133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25509065 + 25509066.

It is an arithmetic number, because the mean of its divisors is an integer number (25509066).

Almost surely, 251018131 is an apocalyptic number.

51018131 is a deficient number, since it is larger than the sum of its proper divisors (1).

51018131 is an equidigital number, since it uses as much as digits as its factorization.

51018131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 20.

The square root of 51018131 is about 7142.6977396499. The cubic root of 51018131 is about 370.8869178246.

Adding to 51018131 its reverse (13181015), we get a palindrome (64199146).

The spelling of 51018131 in words is "fifty-one million, eighteen thousand, one hundred thirty-one".