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51021112530541 is a prime number
BaseRepresentation
bin10111001100111010001110…
…10010011101011001101101
320200122120102001112100212111
423212131013102131121231
523141412214301434131
6300302435302404021
713514103505626256
oct1346350722353155
9220576361470774
1051021112530541
1115290a289a672a
125880297430611
132261368a1372a
14c856139b7b2d
155d7299b50ab1
hex2e674749d66d

51021112530541 has 2 divisors, whose sum is σ = 51021112530542. Its totient is φ = 51021112530540.

The previous prime is 51021112530497. The next prime is 51021112530547. The reversal of 51021112530541 is 14503521112015.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50415026925316 + 606085605225 = 7100354^2 + 778515^2 .

It is a cyclic number.

It is not a de Polignac number, because 51021112530541 - 237 = 50883673577069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51021112530547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25510556265270 + 25510556265271.

It is an arithmetic number, because the mean of its divisors is an integer number (25510556265271).

Almost surely, 251021112530541 is an apocalyptic number.

It is an amenable number.

51021112530541 is a deficient number, since it is larger than the sum of its proper divisors (1).

51021112530541 is an equidigital number, since it uses as much as digits as its factorization.

51021112530541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6000, while the sum is 31.

Adding to 51021112530541 its reverse (14503521112015), we get a palindrome (65524633642556).

The spelling of 51021112530541 in words is "fifty-one trillion, twenty-one billion, one hundred twelve million, five hundred thirty thousand, five hundred forty-one".