Base | Representation |
---|---|
bin | 10111001100111010001110… |
… | …10010011101011001101101 |
3 | 20200122120102001112100212111 |
4 | 23212131013102131121231 |
5 | 23141412214301434131 |
6 | 300302435302404021 |
7 | 13514103505626256 |
oct | 1346350722353155 |
9 | 220576361470774 |
10 | 51021112530541 |
11 | 15290a289a672a |
12 | 5880297430611 |
13 | 2261368a1372a |
14 | c856139b7b2d |
15 | 5d7299b50ab1 |
hex | 2e674749d66d |
51021112530541 has 2 divisors, whose sum is σ = 51021112530542. Its totient is φ = 51021112530540.
The previous prime is 51021112530497. The next prime is 51021112530547. The reversal of 51021112530541 is 14503521112015.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 50415026925316 + 606085605225 = 7100354^2 + 778515^2 .
It is a cyclic number.
It is not a de Polignac number, because 51021112530541 - 237 = 50883673577069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51021112530547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25510556265270 + 25510556265271.
It is an arithmetic number, because the mean of its divisors is an integer number (25510556265271).
Almost surely, 251021112530541 is an apocalyptic number.
It is an amenable number.
51021112530541 is a deficient number, since it is larger than the sum of its proper divisors (1).
51021112530541 is an equidigital number, since it uses as much as digits as its factorization.
51021112530541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6000, while the sum is 31.
Adding to 51021112530541 its reverse (14503521112015), we get a palindrome (65524633642556).
The spelling of 51021112530541 in words is "fifty-one trillion, twenty-one billion, one hundred twelve million, five hundred thirty thousand, five hundred forty-one".
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