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5102540473 is a prime number
BaseRepresentation
bin1001100000010001…
…01001011010111001
3111011121022220122111
410300020221122321
540422222243343
62202153052321
7240305610202
oct46010513271
914147286574
105102540473
1121892841a8
12ba49b70a1
13634181824
143659545a9
151ece5dc9d
hex1302296b9

5102540473 has 2 divisors, whose sum is σ = 5102540474. Its totient is φ = 5102540472.

The previous prime is 5102540437. The next prime is 5102540489. The reversal of 5102540473 is 3740452015.

Together with previous prime (5102540437) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4049667769 + 1052872704 = 63637^2 + 32448^2 .

It is a cyclic number.

It is not a de Polignac number, because 5102540473 - 29 = 5102539961 is a prime.

It is not a weakly prime, because it can be changed into another prime (5102540413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2551270236 + 2551270237.

It is an arithmetic number, because the mean of its divisors is an integer number (2551270237).

Almost surely, 25102540473 is an apocalyptic number.

It is an amenable number.

5102540473 is a deficient number, since it is larger than the sum of its proper divisors (1).

5102540473 is an equidigital number, since it uses as much as digits as its factorization.

5102540473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16800, while the sum is 31.

The square root of 5102540473 is about 71432.0689396576. The cubic root of 5102540473 is about 1721.5863848999.

Adding to 5102540473 its reverse (3740452015), we get a palindrome (8842992488).

The spelling of 5102540473 in words is "five billion, one hundred two million, five hundred forty thousand, four hundred seventy-three".