5102540437 has 2 divisors, whose sum is σ = 5102540438. Its totient is φ = 5102540436.

The previous prime is 5102540431. The next prime is 5102540473. The reversal of 5102540437 is 7340452015.

Together with next prime (5102540473) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4479089476 + 623450961 = 66926^2 + 24969^2 .

It is a cyclic number.

It is not a de Polignac number, because 5102540437 - 2⁷ = 5102540309 is a prime.

It is a super-2 number, since 2×5102540437² = 52071837822440301938, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5102540399 and 5102540408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5102540431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2551270218 + 2551270219.

It is an arithmetic number, because the mean of its divisors is an integer number (2551270219).

Almost surely, 2^5102540437 is an apocalyptic number.

It is an amenable number.

5102540437 is a deficient number, since it is larger than the sum of its proper divisors (1).

5102540437 is an equidigital number, since it uses as much as digits as its factorization.

5102540437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16800, while the sum is 31.

The square root of 5102540437 is about 71432.0686876700. The cubic root of 5102540437 is about 1721.5863808511.

The spelling of 5102540437 in words is "five billion, one hundred two million, five hundred forty thousand, four hundred thirty-seven".