Base | Representation |
---|---|
bin | 10111001101001110100010… |
… | …00101110010100111111101 |
3 | 20200200121112211022201022022 |
4 | 23212213101011302213331 |
5 | 23142102031141244442 |
6 | 300311441143325525 |
7 | 13514640614164241 |
oct | 1346472105624775 |
9 | 220617484281268 |
10 | 51032014399997 |
11 | 152956127aa5a4 |
12 | 588241a4508a5 |
13 | 22623b5500467 |
14 | c85d69822421 |
15 | 5d76d6ca93d2 |
hex | 2e69d11729fd |
51032014399997 has 2 divisors, whose sum is σ = 51032014399998. Its totient is φ = 51032014399996.
The previous prime is 51032014399991. The next prime is 51032014400057. The reversal of 51032014399997 is 79999341023015.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 35724600724036 + 15307413675961 = 5977006^2 + 3912469^2 .
It is a cyclic number.
It is not a de Polignac number, because 51032014399997 - 220 = 51032013351421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51032014399991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25516007199998 + 25516007199999.
It is an arithmetic number, because the mean of its divisors is an integer number (25516007199999).
Almost surely, 251032014399997 is an apocalyptic number.
It is an amenable number.
51032014399997 is a deficient number, since it is larger than the sum of its proper divisors (1).
51032014399997 is an equidigital number, since it uses as much as digits as its factorization.
51032014399997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16533720, while the sum is 62.
The spelling of 51032014399997 in words is "fifty-one trillion, thirty-two billion, fourteen million, three hundred ninety-nine thousand, nine hundred ninety-seven".
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