Base | Representation |
---|---|
bin | 1001100000011100… |
… | …10101011011001101 |
3 | 111011201010122212101 |
4 | 10300032111123031 |
5 | 40423113001222 |
6 | 2202245035101 |
7 | 240324360061 |
oct | 46016253315 |
9 | 14151118771 |
10 | 5104031437 |
11 | 218a1023aa |
12 | ba53b5a91 |
13 | 63458435b |
14 | 365c21aa1 |
15 | 1ed155927 |
hex | 1303956cd |
5104031437 has 2 divisors, whose sum is σ = 5104031438. Its totient is φ = 5104031436.
The previous prime is 5104031417. The next prime is 5104031441. The reversal of 5104031437 is 7341304015.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4595348521 + 508682916 = 67789^2 + 22554^2 .
It is a cyclic number.
It is not a de Polignac number, because 5104031437 - 211 = 5104029389 is a prime.
It is a super-2 number, since 2×51040314372 = 52102273819768569938, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5104031417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2552015718 + 2552015719.
It is an arithmetic number, because the mean of its divisors is an integer number (2552015719).
Almost surely, 25104031437 is an apocalyptic number.
It is an amenable number.
5104031437 is a deficient number, since it is larger than the sum of its proper divisors (1).
5104031437 is an equidigital number, since it uses as much as digits as its factorization.
5104031437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 28.
The square root of 5104031437 is about 71442.5044143891. The cubic root of 5104031437 is about 1721.7540512724.
The spelling of 5104031437 in words is "five billion, one hundred four million, thirty-one thousand, four hundred thirty-seven".
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