Base | Representation |
---|---|
bin | 100101001001010001000… |
… | …1111111000110010011011 |
3 | 200002001021012122012001111 |
4 | 1022102202033320302123 |
5 | 1132120313131041103 |
6 | 14505134224401151 |
7 | 1034556131253211 |
oct | 112224217706233 |
9 | 20061235565044 |
10 | 5105143221403 |
11 | 1699096291a65 |
12 | 6a54b21761b7 |
13 | 2b054a2c9c84 |
14 | 13913990acb1 |
15 | 8cbe325386d |
hex | 4a4a23f8c9b |
5105143221403 has 2 divisors, whose sum is σ = 5105143221404. Its totient is φ = 5105143221402.
The previous prime is 5105143221401. The next prime is 5105143221413. The reversal of 5105143221403 is 3041223415015.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5105143221403 - 21 = 5105143221401 is a prime.
It is a super-2 number, since 2×51051432214032 (a number of 26 digits) contains 22 as substring.
Together with 5105143221401, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (5105143221401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2552571610701 + 2552571610702.
It is an arithmetic number, because the mean of its divisors is an integer number (2552571610702).
Almost surely, 25105143221403 is an apocalyptic number.
5105143221403 is a deficient number, since it is larger than the sum of its proper divisors (1).
5105143221403 is an equidigital number, since it uses as much as digits as its factorization.
5105143221403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 5105143221403 its reverse (3041223415015), we get a palindrome (8146366636418).
The spelling of 5105143221403 in words is "five trillion, one hundred five billion, one hundred forty-three million, two hundred twenty-one thousand, four hundred three".
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