Base | Representation |
---|---|
bin | 100101001010001001011… |
… | …1111001000011011101011 |
3 | 200002020011000200221102001 |
4 | 1022110102333020123223 |
5 | 1132133201332420233 |
6 | 14510050032351431 |
7 | 1034654036212231 |
oct | 112242277103353 |
9 | 20066130627361 |
10 | 5107034654443 |
11 | 1699976a16667 |
12 | 6a593b6a5577 |
13 | 2b078c121317 |
14 | 139278bc4951 |
15 | 8cca431d27d |
hex | 4a512fc86eb |
5107034654443 has 2 divisors, whose sum is σ = 5107034654444. Its totient is φ = 5107034654442.
The previous prime is 5107034654369. The next prime is 5107034654489. The reversal of 5107034654443 is 3444564307015.
It is an a-pointer prime, because the next prime (5107034654489) can be obtained adding 5107034654443 to its sum of digits (46).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5107034654443 - 225 = 5107001100011 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5107034654393 and 5107034654402.
It is not a weakly prime, because it can be changed into another prime (5107034651443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2553517327221 + 2553517327222.
It is an arithmetic number, because the mean of its divisors is an integer number (2553517327222).
Almost surely, 25107034654443 is an apocalyptic number.
5107034654443 is a deficient number, since it is larger than the sum of its proper divisors (1).
5107034654443 is an equidigital number, since it uses as much as digits as its factorization.
5107034654443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2419200, while the sum is 46.
The spelling of 5107034654443 in words is "five trillion, one hundred seven billion, thirty-four million, six hundred fifty-four thousand, four hundred forty-three".
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