Base | Representation |
---|---|
bin | 10111001110101010000001… |
… | …11000010101010001110011 |
3 | 20200212022100002120101212100 |
4 | 23213111000320111101303 |
5 | 23143403130421412441 |
6 | 300350203235031443 |
7 | 13521330063516006 |
oct | 1347250070252163 |
9 | 220768302511770 |
10 | 51081134560371 |
11 | 15304429860063 |
12 | 588ba4873b583 |
13 | 2266c12bb4c06 |
14 | c884a936353d |
15 | 5d8b0e2a5cb6 |
hex | 2e7540e15473 |
51081134560371 has 24 divisors (see below), whose sum is σ = 75382098377040. Its totient is φ = 33324330986496.
The previous prime is 51081134560369. The next prime is 51081134560397. The reversal of 51081134560371 is 17306543118015.
51081134560371 is a `hidden beast` number, since 5 + 1 + 0 + 8 + 1 + 1 + 34 + 5 + 603 + 7 + 1 = 666.
It is not a de Polignac number, because 51081134560371 - 21 = 51081134560369 is a prime.
It is not an unprimeable number, because it can be changed into a prime (51081134560171) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 328642425 + ... + 328797818.
It is an arithmetic number, because the mean of its divisors is an integer number (3140920765710).
Almost surely, 251081134560371 is an apocalyptic number.
51081134560371 is a deficient number, since it is larger than the sum of its proper divisors (24300963816669).
51081134560371 is a wasteful number, since it uses less digits than its factorization.
51081134560371 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 657440435 (or 657440432 counting only the distinct ones).
The product of its (nonzero) digits is 302400, while the sum is 45.
Adding to 51081134560371 its reverse (17306543118015), we get a palindrome (68387677678386).
The spelling of 51081134560371 in words is "fifty-one trillion, eighty-one billion, one hundred thirty-four million, five hundred sixty thousand, three hundred seventy-one".
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