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5108119781 is a prime number
BaseRepresentation
bin1001100000111011…
…11011100011100101
3111011222211101000112
410300131323203211
540430134313111
62202512422405
7240404205332
oct46035734345
914158741015
105108119781
112191444aa6
12ba6847a05
136353861ab
143665a7989
151ed6b1e8b
hex13077b8e5

5108119781 has 2 divisors, whose sum is σ = 5108119782. Its totient is φ = 5108119780.

The previous prime is 5108119741. The next prime is 5108119789. The reversal of 5108119781 is 1879118015.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5090822500 + 17297281 = 71350^2 + 4159^2 .

It is a cyclic number.

It is not a de Polignac number, because 5108119781 - 26 = 5108119717 is a prime.

It is a super-2 number, since 2×51081197812 = 52185775394086975922, which contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5108119789) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2554059890 + 2554059891.

It is an arithmetic number, because the mean of its divisors is an integer number (2554059891).

Almost surely, 25108119781 is an apocalyptic number.

It is an amenable number.

5108119781 is a deficient number, since it is larger than the sum of its proper divisors (1).

5108119781 is an equidigital number, since it uses as much as digits as its factorization.

5108119781 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 41.

The square root of 5108119781 is about 71471.1115136738. Note that the first 3 decimals coincide. The cubic root of 5108119781 is about 1722.2136385820.

The spelling of 5108119781 in words is "five billion, one hundred eight million, one hundred nineteen thousand, seven hundred eighty-one".