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51086518480253 is a prime number
BaseRepresentation
bin10111001110110100000011…
…10010010110110101111101
320200212211020022100212111102
423213122001302112311331
523144000142212332003
6300352453403102445
713521610360213304
oct1347320162266575
9220784208325442
1051086518480253
111530674194a823
125890aab811a25
132267590444c19
14c8885a40143b
155d8d26c96588
hex2e7681c96d7d

51086518480253 has 2 divisors, whose sum is σ = 51086518480254. Its totient is φ = 51086518480252.

The previous prime is 51086518480211. The next prime is 51086518480259. The reversal of 51086518480253 is 35208481568015.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 38312163261124 + 12774355219129 = 6189682^2 + 3574123^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51086518480253 is a prime.

It is a super-3 number, since 3×510865184802533 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51086518480259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25543259240126 + 25543259240127.

It is an arithmetic number, because the mean of its divisors is an integer number (25543259240127).

Almost surely, 251086518480253 is an apocalyptic number.

It is an amenable number.

51086518480253 is a deficient number, since it is larger than the sum of its proper divisors (1).

51086518480253 is an equidigital number, since it uses as much as digits as its factorization.

51086518480253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9216000, while the sum is 56.

The spelling of 51086518480253 in words is "fifty-one trillion, eighty-six billion, five hundred eighteen million, four hundred eighty thousand, two hundred fifty-three".