Base | Representation |
---|---|
bin | 1100001011101… |
… | …0000100001101 |
3 | 10120010211110222 |
4 | 3002322010031 |
5 | 101040000043 |
6 | 5023041125 |
7 | 1160201303 |
oct | 302720415 |
9 | 116124428 |
10 | 51093773 |
11 | 26928565 |
12 | 151401a5 |
13 | a77c203 |
14 | 6b00273 |
15 | 4743d68 |
hex | 30ba10d |
51093773 has 2 divisors, whose sum is σ = 51093774. Its totient is φ = 51093772.
The previous prime is 51093769. The next prime is 51093821. The reversal of 51093773 is 37739015.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 49252324 + 1841449 = 7018^2 + 1357^2 .
It is a cyclic number.
It is not a de Polignac number, because 51093773 - 22 = 51093769 is a prime.
It is a super-2 number, since 2×510937732 = 5221147278751058, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51093733) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25546886 + 25546887.
It is an arithmetic number, because the mean of its divisors is an integer number (25546887).
Almost surely, 251093773 is an apocalyptic number.
It is an amenable number.
51093773 is a deficient number, since it is larger than the sum of its proper divisors (1).
51093773 is an equidigital number, since it uses as much as digits as its factorization.
51093773 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19845, while the sum is 35.
The square root of 51093773 is about 7147.9908365918. The cubic root of 51093773 is about 371.0701257289.
The spelling of 51093773 in words is "fifty-one million, ninety-three thousand, seven hundred seventy-three".
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