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5110013407 is a prime number
BaseRepresentation
bin1001100001001010…
…01001110111011111
3111012010101120120211
410300211021313133
540431130412112
62203021153251
7240426253162
oct46045116737
914163346524
105110013407
112192518784
12ba73bb827
1363589a095
1436693bad9
151ed9380a7
hex130949ddf

5110013407 has 2 divisors, whose sum is σ = 5110013408. Its totient is φ = 5110013406.

The previous prime is 5110013399. The next prime is 5110013449. The reversal of 5110013407 is 7043100115.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5110013407 - 23 = 5110013399 is a prime.

It is a super-2 number, since 2×51100134072 = 52224474039439495298, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5110013107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555006703 + 2555006704.

It is an arithmetic number, because the mean of its divisors is an integer number (2555006704).

Almost surely, 25110013407 is an apocalyptic number.

5110013407 is a deficient number, since it is larger than the sum of its proper divisors (1).

5110013407 is an equidigital number, since it uses as much as digits as its factorization.

5110013407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 420, while the sum is 22.

The square root of 5110013407 is about 71484.3577784679. The cubic root of 5110013407 is about 1722.4264256580.

The spelling of 5110013407 in words is "five billion, one hundred ten million, thirteen thousand, four hundred seven".