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511021425130 = 25277184484269
BaseRepresentation
bin1110110111110110100…
…00000010000111101010
31210212000221222010020021
413123323100002013222
531333032441101010
61030432054351054
751630405305206
oct7337320020752
91725027863207
10511021425130
111877a52aa307
128305805b48a
133925c6373c8
141aa3acadb06
15d45d5058da
hex76fb4021ea

511021425130 has 16 divisors (see below), whose sum is σ = 923159287080. Its totient is φ = 203670631872.

The previous prime is 511021425107. The next prime is 511021425143. The reversal of 511021425130 is 31524120115.

It can be written as a sum of positive squares in 4 ways, for example, as 359061013089 + 151960412041 = 599217^2 + 389821^2 .

It is a super-2 number, since 2×5110214251302 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 511021425095 and 511021425104.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 92239365 + ... + 92244904.

Almost surely, 2511021425130 is an apocalyptic number.

511021425130 is a deficient number, since it is larger than the sum of its proper divisors (412137861950).

511021425130 is a wasteful number, since it uses less digits than its factorization.

511021425130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 184484553.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 511021425130 its reverse (31524120115), we get a palindrome (542545545245).

The spelling of 511021425130 in words is "five hundred eleven billion, twenty-one million, four hundred twenty-five thousand, one hundred thirty".

Divisors: 1 2 5 10 277 554 1385 2770 184484269 368968538 922421345 1844842690 51102142513 102204285026 255510712565 511021425130