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51102512017 is a prime number
BaseRepresentation
bin101111100101111100…
…100111001110010001
311212220102101120210021
4233211330213032101
51314124220341032
635250504103441
73456240120334
oct574574471621
9155812346707
1051102512017
111a744043707
129aa2164b81
134a852bcbbb
14268ad2461b
1514e1575097
hexbe5f27391

51102512017 has 2 divisors, whose sum is σ = 51102512018. Its totient is φ = 51102512016.

The previous prime is 51102511961. The next prime is 51102512047. The reversal of 51102512017 is 71021520115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44065986561 + 7036525456 = 209919^2 + 83884^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51102512017 is a prime.

It is a super-2 number, since 2×511025120172 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51102511982 and 51102512000.

It is not a weakly prime, because it can be changed into another prime (51102512047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25551256008 + 25551256009.

It is an arithmetic number, because the mean of its divisors is an integer number (25551256009).

Almost surely, 251102512017 is an apocalyptic number.

It is an amenable number.

51102512017 is a deficient number, since it is larger than the sum of its proper divisors (1).

51102512017 is an equidigital number, since it uses as much as digits as its factorization.

51102512017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 700, while the sum is 25.

The spelling of 51102512017 in words is "fifty-one billion, one hundred two million, five hundred twelve thousand, seventeen".