Base | Representation |
---|---|
bin | 101111100101111100… |
… | …100111001110010001 |
3 | 11212220102101120210021 |
4 | 233211330213032101 |
5 | 1314124220341032 |
6 | 35250504103441 |
7 | 3456240120334 |
oct | 574574471621 |
9 | 155812346707 |
10 | 51102512017 |
11 | 1a744043707 |
12 | 9aa2164b81 |
13 | 4a852bcbbb |
14 | 268ad2461b |
15 | 14e1575097 |
hex | be5f27391 |
51102512017 has 2 divisors, whose sum is σ = 51102512018. Its totient is φ = 51102512016.
The previous prime is 51102511961. The next prime is 51102512047. The reversal of 51102512017 is 71021520115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 44065986561 + 7036525456 = 209919^2 + 83884^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51102512017 is a prime.
It is a super-2 number, since 2×511025120172 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51102511982 and 51102512000.
It is not a weakly prime, because it can be changed into another prime (51102512047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25551256008 + 25551256009.
It is an arithmetic number, because the mean of its divisors is an integer number (25551256009).
Almost surely, 251102512017 is an apocalyptic number.
It is an amenable number.
51102512017 is a deficient number, since it is larger than the sum of its proper divisors (1).
51102512017 is an equidigital number, since it uses as much as digits as its factorization.
51102512017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 700, while the sum is 25.
The spelling of 51102512017 in words is "fifty-one billion, one hundred two million, five hundred twelve thousand, seventeen".
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