Base | Representation |
---|---|
bin | 101111100101111101… |
… | …011000011000111111 |
3 | 11212220102202211001011 |
4 | 233211331120120333 |
5 | 1314124243312112 |
6 | 35250512300051 |
7 | 3456241616434 |
oct | 574575303077 |
9 | 155812684034 |
10 | 51102713407 |
11 | 1a744170a49 |
12 | 9aa2241627 |
13 | 4a85360775 |
14 | 268ad77b8b |
15 | 14e15b4aa7 |
hex | be5f5863f |
51102713407 has 2 divisors, whose sum is σ = 51102713408. Its totient is φ = 51102713406.
The previous prime is 51102713383. The next prime is 51102713413. The reversal of 51102713407 is 70431720115.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51102713407 is a prime.
It is a super-2 number, since 2×511027134072 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51102713477) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25551356703 + 25551356704.
It is an arithmetic number, because the mean of its divisors is an integer number (25551356704).
Almost surely, 251102713407 is an apocalyptic number.
51102713407 is a deficient number, since it is larger than the sum of its proper divisors (1).
51102713407 is an equidigital number, since it uses as much as digits as its factorization.
51102713407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5880, while the sum is 31.
The spelling of 51102713407 in words is "fifty-one billion, one hundred two million, seven hundred thirteen thousand, four hundred seven".
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