Base | Representation |
---|---|
bin | 101111100101111111… |
… | …000101111010101111 |
3 | 11212220110121121102212 |
4 | 233211333011322233 |
5 | 1314124402141111 |
6 | 35250530041035 |
7 | 3456245465405 |
oct | 574577057257 |
9 | 155813547385 |
10 | 51103162031 |
11 | 1a744448009 |
12 | 9aa241917b |
13 | 4a85489a1c |
14 | 268b053475 |
15 | 14e165298b |
hex | be5fc5eaf |
51103162031 has 2 divisors, whose sum is σ = 51103162032. Its totient is φ = 51103162030.
The previous prime is 51103162009. The next prime is 51103162037. The reversal of 51103162031 is 13026130115.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51103162031 is a prime.
It is a super-2 number, since 2×511031620312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51103161988 and 51103162006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51103162037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25551581015 + 25551581016.
It is an arithmetic number, because the mean of its divisors is an integer number (25551581016).
Almost surely, 251103162031 is an apocalyptic number.
51103162031 is a deficient number, since it is larger than the sum of its proper divisors (1).
51103162031 is an equidigital number, since it uses as much as digits as its factorization.
51103162031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 51103162031 its reverse (13026130115), we get a palindrome (64129292146).
The spelling of 51103162031 in words is "fifty-one billion, one hundred three million, one hundred sixty-two thousand, thirty-one".
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