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51103162031 is a prime number
BaseRepresentation
bin101111100101111111…
…000101111010101111
311212220110121121102212
4233211333011322233
51314124402141111
635250530041035
73456245465405
oct574577057257
9155813547385
1051103162031
111a744448009
129aa241917b
134a85489a1c
14268b053475
1514e165298b
hexbe5fc5eaf

51103162031 has 2 divisors, whose sum is σ = 51103162032. Its totient is φ = 51103162030.

The previous prime is 51103162009. The next prime is 51103162037. The reversal of 51103162031 is 13026130115.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51103162031 is a prime.

It is a super-2 number, since 2×511031620312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51103161988 and 51103162006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51103162037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25551581015 + 25551581016.

It is an arithmetic number, because the mean of its divisors is an integer number (25551581016).

Almost surely, 251103162031 is an apocalyptic number.

51103162031 is a deficient number, since it is larger than the sum of its proper divisors (1).

51103162031 is an equidigital number, since it uses as much as digits as its factorization.

51103162031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 51103162031 its reverse (13026130115), we get a palindrome (64129292146).

The spelling of 51103162031 in words is "fifty-one billion, one hundred three million, one hundred sixty-two thousand, thirty-one".