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51103265641 is a prime number
BaseRepresentation
bin101111100101111111…
…011111001101101001
311212220110210212120021
4233211333133031221
51314124414000031
635250532200441
73456246406441
oct574577371551
9155813725507
1051103265641
111a74450893a
129aa2469121
134a854c4c2c
14268b07d121
1514e1673511
hexbe5fdf369

51103265641 has 2 divisors, whose sum is σ = 51103265642. Its totient is φ = 51103265640.

The previous prime is 51103265623. The next prime is 51103265669. The reversal of 51103265641 is 14656230115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31329000000 + 19774265641 = 177000^2 + 140621^2 .

It is a cyclic number.

It is not a de Polignac number, because 51103265641 - 213 = 51103257449 is a prime.

It is a super-2 number, since 2×511032656412 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51103265597 and 51103265606.

It is not a weakly prime, because it can be changed into another prime (51103265341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25551632820 + 25551632821.

It is an arithmetic number, because the mean of its divisors is an integer number (25551632821).

Almost surely, 251103265641 is an apocalyptic number.

It is an amenable number.

51103265641 is a deficient number, since it is larger than the sum of its proper divisors (1).

51103265641 is an equidigital number, since it uses as much as digits as its factorization.

51103265641 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 34.

Adding to 51103265641 its reverse (14656230115), we get a palindrome (65759495756).

The spelling of 51103265641 in words is "fifty-one billion, one hundred three million, two hundred sixty-five thousand, six hundred forty-one".