Base | Representation |
---|---|
bin | 101111100110000010… |
… | …110010100011100100 |
3 | 11212220112102212000201 |
4 | 233212002302203210 |
5 | 1314130124200200 |
6 | 35251002520244 |
7 | 3456256643305 |
oct | 574602624344 |
9 | 155815385021 |
10 | 51104131300 |
11 | 1a744a4a262 |
12 | 9aa2806084 |
13 | 4a85738c61 |
14 | 268b2267ac |
15 | 14e1794c6a |
hex | be60b28e4 |
51104131300 has 36 divisors (see below), whose sum is σ = 110912276160. Its totient is φ = 20438645920.
The previous prime is 51104131283. The next prime is 51104131349. The reversal of 51104131300 is 313140115.
It is a super-2 number, since 2×511041313002 (a number of 22 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 722097 + ... + 789703.
It is an arithmetic number, because the mean of its divisors is an integer number (3080896560).
Almost surely, 251104131300 is an apocalyptic number.
51104131300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
51104131300 is an abundant number, since it is smaller than the sum of its proper divisors (59808144860).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51104131300 is a wasteful number, since it uses less digits than its factorization.
51104131300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 75180 (or 75173 counting only the distinct ones).
The product of its (nonzero) digits is 180, while the sum is 19.
Adding to 51104131300 its reverse (313140115), we get a palindrome (51417271415).
The spelling of 51104131300 in words is "fifty-one billion, one hundred four million, one hundred thirty-one thousand, three hundred".
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