Base | Representation |
---|---|
bin | 111010000110010101111110… |
… | …1011110111010011010011011 |
3 | 2111000110110001212010120211211 |
4 | 1310030223331132322122123 |
5 | 1013440431113220433313 |
6 | 5010522534355403551 |
7 | 212433541146111442 |
oct | 16414537536723233 |
9 | 2430413055116754 |
10 | 511045231421083 |
11 | 13892007a240917 |
12 | 49397ba5bb35b7 |
13 | 18c20487934c18 |
14 | 902aa14ca1d59 |
15 | 3e136d4ea9e3d |
hex | 1d0cafd7ba69b |
511045231421083 has 2 divisors, whose sum is σ = 511045231421084. Its totient is φ = 511045231421082.
The previous prime is 511045231420979. The next prime is 511045231421089. The reversal of 511045231421083 is 380124132540115.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-511045231421083 is a prime.
It is a super-2 number, since 2×5110452314210832 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (511045231421089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255522615710541 + 255522615710542.
It is an arithmetic number, because the mean of its divisors is an integer number (255522615710542).
Almost surely, 2511045231421083 is an apocalyptic number.
511045231421083 is a deficient number, since it is larger than the sum of its proper divisors (1).
511045231421083 is an equidigital number, since it uses as much as digits as its factorization.
511045231421083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 115200, while the sum is 40.
Adding to 511045231421083 its reverse (380124132540115), we get a palindrome (891169363961198).
The spelling of 511045231421083 in words is "five hundred eleven trillion, forty-five billion, two hundred thirty-one million, four hundred twenty-one thousand, eighty-three".
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