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511053635441 is a prime number
BaseRepresentation
bin1110110111111010010…
…10111001111101110001
31210212010012120120110202
413123331022321331301
531333114212313231
61030435205004545
751631246140626
oct7337512717561
91725105516422
10511053635441
111878114aa3a8
12830669b3755
133926620446b
141aa4129634d
15d4612695cb
hex76fd2b9f71

511053635441 has 2 divisors, whose sum is σ = 511053635442. Its totient is φ = 511053635440.

The previous prime is 511053635413. The next prime is 511053635471. The reversal of 511053635441 is 144536350115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 478393555600 + 32660079841 = 691660^2 + 180721^2 .

It is a cyclic number.

It is not a de Polignac number, because 511053635441 - 26 = 511053635377 is a prime.

It is a super-2 number, since 2×5110536354412 (a number of 24 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 511053635395 and 511053635404.

It is not a weakly prime, because it can be changed into another prime (511053635471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255526817720 + 255526817721.

It is an arithmetic number, because the mean of its divisors is an integer number (255526817721).

Almost surely, 2511053635441 is an apocalyptic number.

It is an amenable number.

511053635441 is a deficient number, since it is larger than the sum of its proper divisors (1).

511053635441 is an equidigital number, since it uses as much as digits as its factorization.

511053635441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108000, while the sum is 38.

Adding to 511053635441 its reverse (144536350115), we get a palindrome (655589985556).

The spelling of 511053635441 in words is "five hundred eleven billion, fifty-three million, six hundred thirty-five thousand, four hundred forty-one".