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5110600099477 is a prime number
BaseRepresentation
bin100101001011110011110…
…0000001110011010010101
3200002120100111201022111211
41022113213200032122111
51132213002111140402
614511435520301421
71035141302044555
oct112274740163225
920076314638454
105110600099477
1116a0436583254
126a6575771871
132b0c099c3102
141394d653b165
158ce123564d7
hex4a5e780e695

5110600099477 has 2 divisors, whose sum is σ = 5110600099478. Its totient is φ = 5110600099476.

The previous prime is 5110600099459. The next prime is 5110600099483. The reversal of 5110600099477 is 7749900060115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4923845612676 + 186754486801 = 2218974^2 + 432151^2 .

It is a cyclic number.

It is not a de Polignac number, because 5110600099477 - 27 = 5110600099349 is a prime.

It is a super-2 number, since 2×51106000994772 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 5110600099477.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5110600099417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555300049738 + 2555300049739.

It is an arithmetic number, because the mean of its divisors is an integer number (2555300049739).

Almost surely, 25110600099477 is an apocalyptic number.

It is an amenable number.

5110600099477 is a deficient number, since it is larger than the sum of its proper divisors (1).

5110600099477 is an equidigital number, since it uses as much as digits as its factorization.

5110600099477 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 476280, while the sum is 49.

The spelling of 5110600099477 in words is "five trillion, one hundred ten billion, six hundred million, ninety-nine thousand, four hundred seventy-seven".