Base | Representation |
---|---|
bin | 101111100110001001… |
… | …111110011100011011 |
3 | 11212220122222112222111 |
4 | 233212021332130123 |
5 | 1314131114440003 |
6 | 35251111133151 |
7 | 3456311650201 |
oct | 574611763433 |
9 | 155818875874 |
10 | 51106015003 |
11 | 1a74601653a |
12 | 9aa33741b7 |
13 | 4a85c48484 |
14 | 268b597071 |
15 | 14e1a17e6d |
hex | be627e71b |
51106015003 has 2 divisors, whose sum is σ = 51106015004. Its totient is φ = 51106015002.
The previous prime is 51106015001. The next prime is 51106015027. The reversal of 51106015003 is 30051060115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51106015003 - 21 = 51106015001 is a prime.
It is a super-2 number, since 2×511060150032 (a number of 22 digits) contains 22 as substring.
Together with 51106015001, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (51106015001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25553007501 + 25553007502.
It is an arithmetic number, because the mean of its divisors is an integer number (25553007502).
Almost surely, 251106015003 is an apocalyptic number.
51106015003 is a deficient number, since it is larger than the sum of its proper divisors (1).
51106015003 is an equidigital number, since it uses as much as digits as its factorization.
51106015003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 450, while the sum is 22.
Adding to 51106015003 its reverse (30051060115), we get a palindrome (81157075118).
The spelling of 51106015003 in words is "fifty-one billion, one hundred six million, fifteen thousand, three".
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