Base | Representation |
---|---|
bin | 10111001111011011101101… |
… | …00100010001100000101011 |
3 | 20200221212011210211221121221 |
4 | 23213231312210101200223 |
5 | 23144322241044403444 |
6 | 300410333532442511 |
7 | 13523263024250614 |
oct | 1347556644214053 |
9 | 220855153757557 |
10 | 51107805075499 |
11 | 153147756508a7 |
12 | 5895050619437 |
13 | 22695a3543303 |
14 | c898b9518c0b |
15 | 5d9670955a84 |
hex | 2e7b7691182b |
51107805075499 has 2 divisors, whose sum is σ = 51107805075500. Its totient is φ = 51107805075498.
The previous prime is 51107805075497. The next prime is 51107805075557. The reversal of 51107805075499 is 99457050870115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51107805075499 - 21 = 51107805075497 is a prime.
It is a super-2 number, since 2×511078050754992 (a number of 28 digits) contains 22 as substring.
Together with 51107805075497, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (51107805075497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25553902537749 + 25553902537750.
It is an arithmetic number, because the mean of its divisors is an integer number (25553902537750).
Almost surely, 251107805075499 is an apocalyptic number.
51107805075499 is a deficient number, since it is larger than the sum of its proper divisors (1).
51107805075499 is an equidigital number, since it uses as much as digits as its factorization.
51107805075499 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15876000, while the sum is 61.
The spelling of 51107805075499 in words is "fifty-one trillion, one hundred seven billion, eight hundred five million, seventy-five thousand, four hundred ninety-nine".
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