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511101091913 is a prime number
BaseRepresentation
bin1110110111111111111…
…11111100000001001001
31210212020111212121111212
413123333333330001021
531333213334420123
61030444022102505
751632363412656
oct7337777740111
91725214777455
10511101091913
11187836273125
128307a87aa35
1339272cabc09
141aa476cac2d
15d4654e0878
hex76ffffc049

511101091913 has 2 divisors, whose sum is σ = 511101091914. Its totient is φ = 511101091912.

The previous prime is 511101091901. The next prime is 511101091927. The reversal of 511101091913 is 319190101115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 443273660944 + 67827430969 = 665788^2 + 260437^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-511101091913 is a prime.

It is a super-2 number, since 2×5111010919132 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 511101091913.

It is not a weakly prime, because it can be changed into another prime (511101091013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255550545956 + 255550545957.

It is an arithmetic number, because the mean of its divisors is an integer number (255550545957).

Almost surely, 2511101091913 is an apocalyptic number.

It is an amenable number.

511101091913 is a deficient number, since it is larger than the sum of its proper divisors (1).

511101091913 is an equidigital number, since it uses as much as digits as its factorization.

511101091913 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1215, while the sum is 32.

The spelling of 511101091913 in words is "five hundred eleven billion, one hundred one million, ninety-one thousand, nine hundred thirteen".