Base | Representation |
---|---|
bin | 10111001111100000000010… |
… | …11101001010101010111101 |
3 | 20200222002012012110211221121 |
4 | 23213300001131022222331 |
5 | 23144342024110324001 |
6 | 300411401052230541 |
7 | 13523404540336303 |
oct | 1347600135125275 |
9 | 220862165424847 |
10 | 51110135245501 |
11 | 153157609a9032 |
12 | 58955a0a6b451 |
13 | 226988521c927 |
14 | c89a5ab9c273 |
15 | 5d975a2d66a1 |
hex | 2e7c0174aabd |
51110135245501 has 32 divisors (see below), whose sum is σ = 55578222741888. Its totient is φ = 46812735836160.
The previous prime is 51110135245493. The next prime is 51110135245531. The reversal of 51110135245501 is 10554253101115.
It is a cyclic number.
It is not a de Polignac number, because 51110135245501 - 23 = 51110135245493 is a prime.
It is a super-2 number, since 2×511101352455012 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51110135245531) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 908321970 + ... + 908378236.
It is an arithmetic number, because the mean of its divisors is an integer number (1736819460684).
Almost surely, 251110135245501 is an apocalyptic number.
It is an amenable number.
51110135245501 is a deficient number, since it is larger than the sum of its proper divisors (4468087496387).
51110135245501 is a wasteful number, since it uses less digits than its factorization.
51110135245501 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60861.
The product of its (nonzero) digits is 15000, while the sum is 34.
Adding to 51110135245501 its reverse (10554253101115), we get a palindrome (61664388346616).
The spelling of 51110135245501 in words is "fifty-one trillion, one hundred ten billion, one hundred thirty-five million, two hundred forty-five thousand, five hundred one".
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