Base | Representation |
---|---|
bin | 100101001100000001011… |
… | …1110010101111101001101 |
3 | 200002121112121221110002112 |
4 | 1022120002332111331031 |
5 | 1132214423102321113 |
6 | 14511553342433405 |
7 | 1035155566340315 |
oct | 112300276257515 |
9 | 20077477843075 |
10 | 5111060979533 |
11 | 16a0652750263 |
12 | 6a6683b92865 |
13 | 2b0c8132c0c2 |
14 | 13953b82c445 |
15 | 8ce3ca435a8 |
hex | 4a602f95f4d |
5111060979533 has 2 divisors, whose sum is σ = 5111060979534. Its totient is φ = 5111060979532.
The previous prime is 5111060979517. The next prime is 5111060979539. The reversal of 5111060979533 is 3359790601115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4508602482409 + 602458497124 = 2123347^2 + 776182^2 .
It is a cyclic number.
It is not a de Polignac number, because 5111060979533 - 24 = 5111060979517 is a prime.
It is a super-2 number, since 2×51110609795332 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5111060979539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555530489766 + 2555530489767.
It is an arithmetic number, because the mean of its divisors is an integer number (2555530489767).
Almost surely, 25111060979533 is an apocalyptic number.
It is an amenable number.
5111060979533 is a deficient number, since it is larger than the sum of its proper divisors (1).
5111060979533 is an equidigital number, since it uses as much as digits as its factorization.
5111060979533 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 765450, while the sum is 50.
The spelling of 5111060979533 in words is "five trillion, one hundred eleven billion, sixty million, nine hundred seventy-nine thousand, five hundred thirty-three".
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