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51111009974489 is a prime number
BaseRepresentation
bin10111001111100001101011…
…00101111111100011011001
320200222011110011102200112112
423213300311211333203121
523144400322023140424
6300412023540522105
713523435321403503
oct1347606545774331
9220864404380475
1051111009974489
111531606a73a953
1258957a59b0335
13226999450894a
14c89b0101ad73
155d97abec060e
hex2e7c3597f8d9

51111009974489 has 2 divisors, whose sum is σ = 51111009974490. Its totient is φ = 51111009974488.

The previous prime is 51111009974477. The next prime is 51111009974501. The reversal of 51111009974489 is 98447990011115.

It is a balanced prime because it is at equal distance from previous prime (51111009974477) and next prime (51111009974501).

It can be written as a sum of positive squares in only one way, i.e., 51101266705225 + 9743269264 = 7148515^2 + 98708^2 .

It is a cyclic number.

It is not a de Polignac number, because 51111009974489 - 224 = 51110993197273 is a prime.

It is a super-2 number, since 2×511110099744892 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (51111009974389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25555504987244 + 25555504987245.

It is an arithmetic number, because the mean of its divisors is an integer number (25555504987245).

Almost surely, 251111009974489 is an apocalyptic number.

It is an amenable number.

51111009974489 is a deficient number, since it is larger than the sum of its proper divisors (1).

51111009974489 is an equidigital number, since it uses as much as digits as its factorization.

51111009974489 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3265920, while the sum is 59.

The spelling of 51111009974489 in words is "fifty-one trillion, one hundred eleven billion, nine million, nine hundred seventy-four thousand, four hundred eighty-nine".