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51113011 is a prime number
BaseRepresentation
bin1100001011111…
…0110000110011
310120011210212111
43002332300303
5101041104021
65023310151
71160311345
oct302766063
9116153774
1051113011
1126940a64
121514b357
13a787bb1
146b07295
1547498e1
hex30bec33

51113011 has 2 divisors, whose sum is σ = 51113012. Its totient is φ = 51113010.

The previous prime is 51113009. The next prime is 51113053. The reversal of 51113011 is 11031115.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 51113011 - 21 = 51113009 is a prime.

It is a super-2 number, since 2×511130112 = 5225079786972242, which contains 22 as substring.

Together with 51113009, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 51112982 and 51113000.

It is not a weakly prime, because it can be changed into another prime (51113071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25556505 + 25556506.

It is an arithmetic number, because the mean of its divisors is an integer number (25556506).

Almost surely, 251113011 is an apocalyptic number.

51113011 is a deficient number, since it is larger than the sum of its proper divisors (1).

51113011 is an equidigital number, since it uses as much as digits as its factorization.

51113011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 13.

The square root of 51113011 is about 7149.3364027719. The cubic root of 51113011 is about 371.1166920773.

Adding to 51113011 its reverse (11031115), we get a palindrome (62144126).

The spelling of 51113011 in words is "fifty-one million, one hundred thirteen thousand, eleven".